Heeeeelp!!!

typaradise · #1 $Old$ 04-19-2008, 08:52 PM

Hi Everyone,

I am stuck on my last two problems. I have done 62 out of 64 and brain is too tired to calculate two plus two. If anyone can help me solve the last two problem step by step that would be great.

1. x1/2
________
(x3/4)(x-2)

2. 8x8/5(x11/5-9x)

Thank you very much.

TheEmptySet · #2 $Old$ 04-19-2008, 09:04 PM

Quote:

Originally Posted by typaradise $View Post$

Hi Everyone,

I am stuck on my last two problems. I have done 62 out of 64 and brain is too tired to calculate two plus two. If anyone can help me solve the last two problem step by step that would be great.

1. x1/2
________
(x3/4)(x-2)

2. 8x8/5(x11/5-9x)
Thank you very much.

I'm sorry but I don't know what you mean with the above

if you don't know LaTex please use ^ for exponents and lots of parenthesis.

This link will help Help Displaying a formula - Wikipedia, the free encyclopedia

I am guessing your first problem is

$\frac{x^{\frac{1}{2}}}{x^\frac{3}{4}x^{-2}}$

so in non latex (x^(1/2))/((x^(3/4))(x^(-2)))

It I guessed right let me know and I will finish the problem.

Good luck and relax. It sounds like you have had a long night.

typaradise · #3 $Old$ 04-19-2008, 09:26 PM

Yes the first problem is correct except for the denominator x^3/4 multiply by x^-2. The second problem is 8x^8/5(x^11/5-9x).

I am sorry if I was unclear. Thanks for the help.

typaradise · #4 $Old$ 04-19-2008, 09:28 PM

The link is very helpful.

TheEmptySet · #5 $Old$ 04-19-2008, 09:38 PM

Quote:

Originally Posted by typaradise $View Post$

Yes the first problem is correct except for the denominator x^3/4 multiply by x^-2. The second problem is 8x^8/5(x^11/5-9x).

I am sorry if I was unclear. Thanks for the help.

so we need to use our laws of expoents

$\frac{x^{\frac{1}{2}}}{(x^\frac{3}{4})(x^{-2})}$ add exponents in the denominator

$\frac{x^{\frac{1}{2}}}{x^\frac{-5}{4}}$ subtract the exp for the division

$x^{\frac{1}{2}-\frac{-5}{4}}=x^{\frac{9}{4}}$

for the next we distribute

$8x^{8/5}(x^{11/5}-9x)=8x^{19/5}-72x^{13/5}$

good luck.

typaradise · #6 $Old$ 04-19-2008, 10:41 PM

Thank you very much.