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Old April 30th, 2008, 01:44 PM
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Default need help expanding

Can someone please help me expand this, (x-2)^(k+1).
Thanks for the help
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Old April 30th, 2008, 01:54 PM
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Hi

You can use the binomial theorem : (a+b)^n=\sum_{i=0}^n\binom{n}{i}a^i\times b^{n-i}
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Old April 30th, 2008, 01:56 PM
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Originally Posted by cowboys111 View Post
Can someone please help me expand this, (x-2)^(k+1).
Thanks for the help
(a + b)^{m} = \sum_{i = 0}^m {m \choose {m - i}}a^{m - i}b^i

So
(x - 2)^{k+1} = \sum_{i = 0}^{k + 1} {{k + 1} \choose {k + 1 - i}}x^{k + 1 - i}(-2)^i

-Dan
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