number of pairs - Math Help Forum

$Math Help Forum$

$Go Back$		Math Help Forum > Pre-University Math Help > Pre-Algebra and Algebra
$Reload this Page$ number of pairs

Download MHF Flyer

Mark Forums Read

$Reply$

#1

$Old$ June 18th, 2008, 10:17 AM

robkitch $robkitch is offline$

Newbie

Join Date: Jun 2008

Posts: 1

Country:

United States

Thanks: 0

Thanked 0 Times in 0 Posts

$robkitch is on a distinguished road$

$Default$ number of pairs

if u are dealt 5 cards what is the possible way of getting a pair which a pair can be a 2 and a 3

$Reply With Quote$

Advertisement

#2

$Old$ June 18th, 2008, 10:35 AM

$janvdl's Avatar$

$janvdl is offline$

Bar0n

Join Date: Apr 2007

Location: South Africa

Posts: 2,016

Country:

South Africa

Thanks: 1,615

Thanked 1,468 Times in 894 Posts

$janvdl has a brilliant future$ $janvdl has a brilliant future$ $janvdl has a brilliant future$ $janvdl has a brilliant future$ $janvdl has a brilliant future$ $janvdl has a brilliant future$ $janvdl has a brilliant future$ $janvdl has a brilliant future$ $janvdl has a brilliant future$ $janvdl has a brilliant future$ $janvdl has a brilliant future$

$Send a message via MSN to janvdl$

$Default$

Quote:

Originally Posted by robkitch $View Post$

if u are dealt 5 cards what is the possible way of getting a pair which a pair can be a 2 and a 3

EDIT:
Soroban's post gave me greater insight just now

$\frac{ {4 \choose 1} {4 \choose 1}{44 \choose 3} }{{52 \choose 5}} = 0.08153 = 8,15 \ percent \ approx$

__________________
We shall go on to the end, we shall fight in France, we shall fight on the ef-nets and darknets, we shall fight with growing confidence and growing strength in the air, we shall defend our Internets, whatever the cost may be, we shall fight on the beaches, we shall fight on the baywords.org, we shall fight on the /. and on the digg, we shall fight in the courts; we shall never surrender...

- The Pirate Bay Crew

Last edited by janvdl; June 18th, 2008 at 10:48 AM.

$Reply With Quote$

#3

$Old$ June 18th, 2008, 10:41 AM

Soroban $Soroban is online now$

Super Member

Join Date: May 2006

Location: Lexington, MA (USA)

Posts: 7,934

Thanks: 558

Thanked 5,063 Times in 4,054 Posts

$Soroban has a reputation beyond repute$ $Soroban has a reputation beyond repute$ $Soroban has a reputation beyond repute$ $Soroban has a reputation beyond repute$ $Soroban has a reputation beyond repute$ $Soroban has a reputation beyond repute$ $Soroban has a reputation beyond repute$ $Soroban has a reputation beyond repute$ $Soroban has a reputation beyond repute$ $Soroban has a reputation beyond repute$ $Soroban has a reputation beyond repute$

$Default$

Hello, robkitch!

Your English is not quite readable . . .

Quote:

if u are dealt 5 cards what is the possible way of getting a pair which a pair can be a 2 and a 3

I'll take a guess at what you meant . . .

We want five cards: one Deuce, one Trey, and three Others.

To get one Deuce, there are: ${4\choose1} = 4$ ways.

To get one Trey, there are: ${4\choose1} = 4$ ways.

To get three Others, there are: ${44\choose3} = 13,244$ ways.

Therefore, there are: . $4 \times 4 \times 13,244 \:=\:\boxed{211,904\text{ ways}}$

$Reply With Quote$

The following users thank Soroban for this useful post:
janvdl
$Donate to MHF$

$Reply$

« induction | Top | A little bit of help »

Thread Tools
$Show Printable Version$ Show Printable Version $Email this Page$ Email this Page
Display Modes
$Linear Mode$ Linear Mode $Hybrid Mode$ Switch to Hybrid Mode $Threaded Mode$ Switch to Threaded Mode

Posting Rules
You may not post new threads You may not post replies You may not post attachments You may not edit your posts BB code is On Smilies are On [IMG] code is On HTML code is Off Trackbacks are Off Pingbacks are Off Refbacks are Off

Forum Jump

All times are GMT -7. The time now is 03:50 PM.

your link here Sponsors

rv solar, e-learning,

Math Help Forum is a community of maths forums with an emphasis on maths help in all levels of mathematics.
Register to post your math questions or just hang out and try some of our math games or visit the arcade.