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Old 09-05-2008, 05:19 PM
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Exclamation Linear Equations Help Please

If anyone can answer these it would be much appreciated thanks.

1) Solve
-3(p + 9) -4(2p - 6) = 19

2) Solve

2q - 3 q
________+____ = 9

6 4

3) Solve LINEAR INEQUATIONS
-24 > (equal to or greater than) -3(4X - 9) + 2
-

4)

2m + 3 m - 5
______ +______ < 3
2 5

5)
Tickets for a school concert cost $8.50 each for adults and $3.50 each for children. If 700 tickets were sold for the performance and the total raised was $4810, how many adult and children will be attending?
Let 'a' be the number of adults attending and 'c' the number of children
a) Form two equations to represent the situation
b) FInd the mnumber of adults and children attending the concert by solving the equations found in ""above simultaneously

Any help will be appreciated thanks.
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  #2  
Old 09-05-2008, 05:23 PM
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SOrry i posted twice
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  #3  
Old 09-05-2008, 05:30 PM
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Quote:
Originally Posted by Brownhash View Post
If anyone can answer these it would be much appreciated thanks.

1) Solve
-3(p + 9) -4(2p - 6) = 19
First distribute:

-3p-27-8p+24=19

Combine like terms:

-11p-3=9

Now solve for p:

-11p-3=9\implies p=\dots


Quote:
5)
Tickets for a school concert cost $8.50 each for adults and $3.50 each for children. If 700 tickets were sold for the performance and the total raised was $4810, how many adult and children will be attending?
Let 'a' be the number of adults attending and 'c' the number of children
a) Form two equations to represent the situation
700 people [a adults and c] attended the performance.

So one equation is a+c=700

Since the adult tickets were $8.50 and the children tickets were $3.50, and the total price of tickets sold was $4810, this implies that 8.5a+3.5c=4810


Quote:
Originally Posted by Brownhash View Post
b) FInd the mnumber of adults and children attending the concert by solving the equations found in ""above simultaneously

Any help will be appreciated thanks.
Solve the system:

\left\{\begin{array}{rcrcr}a&+&c&=&700\\8.5a&+&3.5c&=&4810\end{array}\right.

Try to solve this [I'd recommend using the elimination technique].

I hope this helps!

--Chris
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Last edited by Chris L T521; 09-05-2008 at 09:12 PM.
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Old 09-05-2008, 05:34 PM
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Ohk thanks the helps me with those one
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Old 09-05-2008, 08:35 PM
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Is there anyone who could please give the full answers to the questions as i need them quite urgently, thanks.
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Old 09-05-2008, 08:52 PM
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[quote=Brownhash;182557]If anyone can answer these it would be much appreciated thanks.

1) Solve
-3(p + 9) -4(2p - 6) = 19

-3p - 27 - 8p + 24 = 19

- 11p = 19 + 27 - 24

- 11p = 22

p = \frac {22}{-11}

p = - 2

Your Q. No. (2) and (4) are not clear. Can you please type them again clearly??

Last edited by Shyam; 09-05-2008 at 09:04 PM.
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Old 09-05-2008, 08:57 PM
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3) Solve LINEAR INEQUATIONS
-24 > (equal to or greater than) -3(4X - 9) + 2

-24 \geq -3(4x-9)+2

-24 \geq -12x+27+2

-24 \geq -12x+29

12x \geq 29+24

x \geq \frac {53}{12}

Your Q. No. (2) and (4) are not clear. Can you please type them again clearly??
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Old 09-05-2008, 09:08 PM
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5)
Tickets for a school concert cost $8.50 each for adults and $3.50 each for children. If 700 tickets were sold for the performance and the total raised was $4810, how many adult and children will be attending?
Let 'a' be the number of adults attending and 'c' the number of children
a) Form two equations to represent the situation
b) FInd the mnumber of adults and children attending the concert by solving the equations found in ""above simultaneously

Any help will be appreciated thanks.[/quote]

Number of adults =a

Number of children =c
(a)
Total number of people attending

a+c=700.................................................. ................eqn(1)

Total money raised

8.50a+3.50c=4810.................................................. ..eqn(2)

eqn(1) and eqn(2) represent the situation.

(b)
Multiply eqn(1) by 3.50,

3.50a+3.50c=2450.................................................. ...eqn(3)

Subtract eqn(3) from eqn(2), we get

5a=2360

a=\frac {2360}{5}

a=472

Put this value of a in eqn(1),

c = 700 - 472

c = 228

There were 472 adults and 228 children.

Last edited by Shyam; 09-05-2008 at 09:19 PM.
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  #9  
Old 09-06-2008, 10:19 PM
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Quote:
Originally Posted by Brownhash View Post
If anyone can answer these it would be much appreciated thanks.

2) Solve

2q - 3 q
________+____ = 9

6 4
Do you mean \frac{2q-3}{6}+\frac{q}{4}=9??

Quote:
Originally Posted by Brownhash View Post
4)

2m + 3 m - 5
______ +______ < 3
2 5

Any help will be appreciated thanks.
Do you mean \frac{2m+3}{2}+\frac{m-5}{5}<3??

--Chris
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  #10  
Old 09-06-2008, 11:34 PM
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Yes thts the one thanks
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