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#1

$Old$ 09-06-2008, 11:25 PM

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$Post$ Logarithm

if:

x=(y+z-x)/log x;
y=(x+z-y)/log y;
z=(x+y-z)/log z;
then prove that :
x^y.y^x=z^y.y^z

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#2

$Old$ 09-07-2008, 12:01 AM

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if

$x = \frac{(y+z-x)}{log x}$ ;
$y = \frac{(x+z-y)}{log y}$ ;
$z = \frac{(x+y-z)}{log z}$ ;

then prove that :

$(x^y)(y^x) = (z^y)(y^z)$

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