Need help on inequalities

Whc15 · #1 $Old$ September 7th, 2008, 02:56 PM

Here are the two problems I need Help on any help would be a great thanks.

l3hl+15<0
and
lxl less then equal to x - 1

For the second one I got all real numbers and the last one iam dont know what to do

Thanks again

Jhevon · #2 $Old$ September 7th, 2008, 03:01 PM

Quote:

Originally Posted by Whc15 $View Post$

Here are the two problems I need Help on any help would be a great thanks.

l3hl+15<0

that's impossible. it doesn't work no matter what h is. if this is your problem, it has no solution

Quote:

and
lxl less then equal to x - 1

for this you have to solve

$-(x - 1) \le x \le x - 1$

this comes from the definition of |x|, which i assume you know

Whc15 · #3 $Old$ September 7th, 2008, 03:06 PM

Thank you for your help

I am still a little confused on the last one would the answer be all real numbers

Jhevon · #4 $Old$ September 7th, 2008, 04:05 PM

Quote:

Originally Posted by Whc15 $View Post$

Thank you for your help

I am still a little confused on the last one would the answer be all real numbers

no, it also has no solution. it would be all real x if $|x| \ge x - 1$

it seems strange that both your answers have no solution. make sure you describe the inequalities correctly

$\ge$ means "greater than or equal to", and

$\le$ means "less than or equal to"

also, check your signs

sportsfan93b · #5 $Old$ September 7th, 2008, 07:00 PM

the first one is impossible because
l3hl<-15 does not work because absolute values always come out positive