Help with transpostion of equation, please?

conpanbear · #1 $Old$ September 21st, 2008, 08:53 PM

Hello everyone, this is my first post, so please have mercy

I've been trying to figure out how to transpose the following equations so that the value in square brackets, [ ] , is the subject. *sorry about not knowing how to insert a square root*

Eqn 2: A = 1 / sqr root(w^2 . R^2 . C^2 + 1) ............ [R . C]

I hope that was clear enough. This is needed for an assignment I have to email before 5pm (current time: 2pm!!) so any assistance in showing me the steps as to how to transpose these would be greatly appreciated!!

Thank you

wisterville · #2 $Old$ September 21st, 2008, 09:19 PM

Hello,

$A^2(w^2R^2C^2+1)=1$ becomes $A^2w^2R^2C^2=1-A^2$ .

I hope it helps.
Bye.

conpanbear · #3 $Old$ September 21st, 2008, 09:30 PM

Thanks for the reply, wisterville. I think I have some idea of how to approach it now

conpanbear · #4 $Old$ September 21st, 2008, 09:38 PM

Can I say that
$R^2C^2 = (1-A^2)/(A^2w^2)$
can be
$RC = sqr root((1-A^2)/(A^2w^2))$ ?
I don't think I can, but I can't figure out how to specifically get RC on its own.

wisterville · #5 $Old$ September 21st, 2008, 10:46 PM

Hello,

$\sqrt{x}=a\iff\begin{cases}x=a^2\\a\geq 0\end{cases}$ .

Of course, even when you have a^2=x, you have to check a>=0 to get a=sqrt x. But for most "problems about transposition of equations", these details are neglected by the composers...

Bye.