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October 3rd, 2008, 09:28 AM
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| |  concentration problem
Freezing weather is coming!
The radiator in my 450 John Deere track loader
is full with 18 quarts of fluid that is 15% antifreeze.
Question: How much must I drain out into a disposable container,
Then retighten drain plug, and pour back 100% pure
antifreeze into radiator to make 18 quarts of 40%
antifreeze. |
October 3rd, 2008, 10:04 AM
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Let x=amount to be drained.
Original mixture less amount drained: (18-x)
Amount of pure antifreeze=.15(18-x)
plus
pure antifreeze is x quarts.
The new mixture is 40%= .4(18)=7.2
So, we have the equation to solve:
.15(18-x)+x=7.2 | | The following users thank galactus for this useful post: | |  |
October 3rd, 2008, 10:37 AM
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i think i get it... so would the answer be -5.3 qts... that doesnt make sense |
October 3rd, 2008, 10:52 AM
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Quote:
Originally Posted by Amelia  i think i get it... so would the answer be -5.3 qts... that doesnt make sense | Check again. I get +5.29
__________________ If you need more than 3 levels of indentation, you're screwed anyway, and should fix your program. - Linus Torvalds
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October 3rd, 2008, 11:00 AM
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| |  thank you so much
is there ne way i could help on one more problem... it has to do with quarters, nickles, and dimes for some reason i cant get it:
I have a collection of nickels, dimes, and quarters
in a money bag worth $7.95. If the number of
quarters is one more than the number of nickels
and the number of dimes is five more than the number
of nickels, find the number of each type of coin.
# Nickels ________
# Dimes_________¬
# Quarters________ |
October 3rd, 2008, 11:05 AM
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Quote:
Originally Posted by Amelia is there ne way i could help on one more problem... it has to do with quarters, nickles, and dimes for some reason i cant get it:
I have a collection of nickels, dimes, and quarters
in a money bag worth $7.95. If the number of
quarters is one more than the number of nickels
and the number of dimes is five more than the number
of nickels, find the number of each type of coin.
# Nickels ________
# Dimes_________¬
# Quarters________ | In future, please make a new thread for each new question.
Okay we have 3 different types of coins.
So:
x + y + z = 7,95
Nickels = x
Quarters = y = x + 1
Dimes = z = x + 5
So you'll just need to substitute the values of these coins. And solve.
a(x) + b(x + 1) + c(x + 5) = 7,95
Where a;b;c are the monetary values of nickels, dimes, and quarters (not respectively!). I don't know the American system.
__________________ If you need more than 3 levels of indentation, you're screwed anyway, and should fix your program. - Linus Torvalds
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October 3rd, 2008, 11:28 AM
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would that make x 8.4 ? im confused  a little: in america dime=.10 nickels=.5 and quarters=.25
i'm confused |
October 3rd, 2008, 11:36 AM
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Quote:
Originally Posted by Amelia would that make x 8.4 ? im confused a little: in america dime=.10 nickels=.5 and quarters=.25
i'm confused | Can you double check the question?
__________________ If you need more than 3 levels of indentation, you're screwed anyway, and should fix your program. - Linus Torvalds
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October 3rd, 2008, 11:44 AM
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yea :
I have a collection of nickels, dimes, and quarters
in a money bag worth $7.95. If the number of
quarters is one more than the number of nickels
and the number of dimes is five more than the number
of nickels, find the number of each type of coin.
# Nickels ________
# Dimes_________¬
# Quarters________
nickels are worth .5
dimes are worth .10
quarters are worth .25
a dollare is 1.00 |
October 3rd, 2008, 11:47 AM
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Quote:
Originally Posted by Amelia yea :
I have a collection of nickels, dimes, and quarters
in a money bag worth $7.95. If the number of
quarters is one more than the number of nickels
and the number of dimes is five more than the number
of nickels, find the number of each type of coin.
# Nickels ________
# Dimes_________¬
# Quarters________
nickels are worth .5
dimes are worth .10
quarters are worth .25
a dollare is 1.00 | Either the question has a fault, or I made a very stupid mistake in my calculations. The latter being very likely.
You have the idea though, that should carry you through.
__________________ If you need more than 3 levels of indentation, you're screwed anyway, and should fix your program. - Linus Torvalds
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October 3rd, 2008, 12:01 PM
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Quote:
Originally Posted by Amelia is there ne way i could help on one more problem... it has to do with quarters, nickles, and dimes for some reason i cant get it:
I have a collection of nickels, dimes, and quarters
in a money bag worth $7.95. If the number of
quarters is one more than the number of nickels
and the number of dimes is five more than the number
of nickels, find the number of each type of coin.
# Nickels ________
# Dimes_________¬
# Quarters________ | Probably this comes too late but I'll post it nevertheless:
Let x denote the number of nickel coins, then the value of these coins is 0.05x
Let x+1 denote the number of quarter coins, then the value of these coins is 0.25(x+1)
Let x+5 denote the number of dime coins, then the value of these coins is 0.1(x+5)
Sum up the values 
Expand the brackets, collect like terms and solve for x.
I've got x =18. | | The Following 2 Users Say Thank You to earboth For This Useful Post: | | |
October 3rd, 2008, 12:01 PM
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oh so then what do i do with the x value? |
October 3rd, 2008, 12:03 PM
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Quote:
Originally Posted by Amelia oh so then what do i do with the x value? | Wait I get it. A nickel is 5 cents, and not 50 cents like you said. That's why Earboth's solution works out so nicely.
__________________ If you need more than 3 levels of indentation, you're screwed anyway, and should fix your program. - Linus Torvalds
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October 3rd, 2008, 12:13 PM
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oh yea.. lol stupid me..
but i took x=18
then that means their are 18 nickels
then 18+1 which is 19 quarters
then 18+5 which is 23..
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