help solving...

Manizzle · #1 $Old$ October 9th, 2008, 12:57 PM

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icemanfan · #2 $Old$ October 9th, 2008, 01:06 PM

$\frac{w-2}{w-6} + 1 = \frac{w+5}{w+4}$

$\frac{w-2}{w-6} + \frac{w-6}{w-6} = \frac{w+5}{w+4}$

$\frac{w-2+w-6}{w-6} = \frac{w+5}{w+4}$

$\frac{2w - 8}{w - 6} = \frac{w+5}{w+4}$

$(2w-8)(w+4) = (w+5)(w-6)$

$2w^2 -32 = w^2 - w - 30$

$2w^2 - 32 - (w^2 - w - 30) = 0$

$2w^2 - 32 - w^2 + w + 30 = 0$

$w^2 + w - 2 = 0$

$(w+2)(w-1) = 0$

$w = -2, 1$