3 Questions URGENT

mikejones · #1 $Old$ November 10th, 2008, 06:28 AM

1. Solve the equation for x: -1/6(x-18)+1/3(x+3)=x+4

2. Subract the mixed numeral (write answer as mixed numeral): 32 7/9 - 18 13/15

3. A ladder is leaning against building. The distance from the bottom of the ladder to the building is 16ft less than the length of the ladder. How high up the side of the building is the top of the ladder is that distance is 2ft less than the length of the ladder?

THANK YOU!!

earboth · #2 $Old$ November 10th, 2008, 06:59 AM

Quote:

Originally Posted by mikejones $View Post$

1. Solve the equation for x: -1/6(x-18)+1/3(x+3)=x+4

2. Subract the mixed numeral (write answer as mixed numeral): 32 7/9 - 18 13/15

3. A ladder is leaning against building. The distance from the bottom of the ladder to the building is 16ft less than the length of the ladder. How high up the side of the building is the top of the ladder is that distance is 2ft less than the length of the ladder?

THANK YOU!!

to #1: Expand the brackets, collect all terms with the variable at the LHS of the equation:

-1/6(x-18)+1/3(x+3)=x+4 <==> -1/6x+3 + 1/3x + 1 = 4 <==>1/6x=0 <==> x = 0

to #2:
There are 2 different ways to do the question:
First transform the mixed numbers into fractions and then subtract
or
subtract integers and fractions separately:

$32\frac79 - 18\frac{13}{15} = (32-18)+\left(\frac79-\frac{13}{15}\right)=14+\left(\frac{70-78}{90}\right)=14-\frac4{45} = 13\frac{41}{45}$

to #3:

You are dealing with a right triangle. Use the Pythagorean theorem. The lengths of the sides are known to you:
a = l -16
b = l - 2
c = l
Therefore:

Solve for l: $(l-16)^2+(l-2)^2 = l^2$

I've got x = 10 or x = 26

You have to decide which solution could be right and why!

mikejones · #3 $Old$ November 10th, 2008, 07:03 AM

Quote:

Originally Posted by earboth $View Post$

to #1: Expand the brackets, collect all terms with the variable at the LHS of the equation:

-1/6(x-18)+1/3(x+3)=x+4 <==> -1/6x+3 + 1/3x + 1 = 4 <==>1/6x=0 <==> x = 0

to #2:
There are 2 different ways to do the question:
First transform the mixed numbers into fractions and then subtract
or
subtract integers and fractions separately:

$32\frac79 - 18\frac{13}{15} = (32-18)+\left(\frac79-\frac{13}{15}\right)=14+\left(\frac{70-78}{90}\right)=14-\frac4{45} = 13\frac{41}{45}$

to #3:

You are dealing with a right triangle. Use the Pythagorean theorem. The lengths of the sides are known to you:
a = l -16
b = l - 2
c = l
Therefore:

Solve for l: $(l-16)^2+(l-2)^2 = l^2$

I've got x = 10 or x = 26

You have to decide which solution could be right and why!

Thanks alot dude..I still have not figured out if #3 is 10 or 26 lol

earboth · #4 $Old$ November 10th, 2008, 07:05 AM

Quote:

Originally Posted by mikejones $View Post$

Thanks alot dude..I still have not figured out if #3 is 10 or 26 lol

If you have to reduce one side by 16 there isn't much choice left!