Quote:
Originally Posted by RBry ...
The next one is to find all the solutions (real and complexe) for:
4x^3 - 4x^2 + 3x - 3 = 0
And, one more using long division: (6x^3 + x^2 - 1) / (x-2)
... |
You can factor the LHS of the equation:
I'll leave the rest for you.
Long division:
Code:
51
(6x^3 + x^2 - 1) ÷ (x - 2) = 6x^2 + 13x + 26 + ------
-(6x^3 - 12x^2) x - 2
--------------------
13x^2 + 0*x
-(13x^2 - 26x)
----------------
26x - 1
-(26x - 52)
---------------
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