Math Help Forum

Math Help Forum Feed Site Feed

Go Back   Math Help Forum > Pre-University Math Help > Pre-Algebra and Algebra
Reply
 
Thread Tools Display Modes
  #1  
Old November 15th, 2008, 01:39 AM
Newbie
 
Join Date: Nov 2008
Posts: 2
Country:
Thanks: 1
Thanked 0 Times in 0 Posts
MWptvf is on a distinguished road
Default If 30 units = 500 and 300 units = 1500 what would say 80 units = ?

I think I need a graphing calculator of some kind.

I want a calculator or a formla for a spread sheet or just a quick way to work out a math problem.

If 30 units = 500 and 300 units = 1500

From this a line on a graph could be drawn that would then tell me the value of any number of units.

what would say 80 units = ?

Maybe I could have explained this better. I hope it makes sense.

Any ideas anyone?

Thanks

MIke
Reply With Quote
Advertisement
 
  #2  
Old November 15th, 2008, 05:46 AM
Arch_Stanton's Avatar
Newbie
 
Join Date: Nov 2008
Posts: 21
Country:
Thanks: 0
Thanked 3 Times in 3 Posts
Arch_Stanton is on a distinguished road
Default

Firstly, we need to find the conversion factor (something like between Celcius <=> Fahrenheit relations):
300u-30u=1500-500
270u=1000
1u=\frac{100}{27}+X
increase of 1u is equal to increase of value \frac{100}{27} and it's obvious, that both scales start in different places, so we need to find the constant number, which will be added during conversion:
30u=500
30*\frac{100}{27}+X=500 \Rightarrow X=\frac{3500}{9}
we can treat it as a function: u(n)=\frac{100}{27}n+\frac{3500}{9}
and then: u(80)=\frac{100}{27}*80+\frac{3500}{9}=\frac{18500}{27}=688,(185)

Of course I assumed, that the units are linear to values, in reality, they might look different. I mean, that grafically our function is a linear function, which might be any other one as well. I hope you kow what I mean.
Reply With Quote
The following users thank Arch_Stanton for this useful post:
Donate to MHF
  #3  
Old November 15th, 2008, 06:09 AM
Newbie
 
Join Date: Nov 2008
Posts: 2
Country:
Thanks: 1
Thanked 0 Times in 0 Posts
MWptvf is on a distinguished road
Default wow....

Well you lost me after the first line

Then I picked it up again at "Of course I assumed,"

I thought you would have said here go to this online calculator and put your numbers in and hit the big red button.

I did it in excel by listing the two columns of data and dividing them up. Crude but it did the job.

Thanks for your reply though.

Regards

Mike
Reply With Quote
  #4  
Old November 15th, 2008, 06:18 AM
Arch_Stanton's Avatar
Newbie
 
Join Date: Nov 2008
Posts: 21
Country:
Thanks: 0
Thanked 3 Times in 3 Posts
Arch_Stanton is on a distinguished road
Default

Since it's a mathematical problem, there is an infinitive amount of functions suiting to these units, just linear is most likely but the values may rise exponentially as well.
Reply With Quote
Reply

Thread Tools
Display Modes

Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

BB code is On
Smilies are On
[IMG] code is On
HTML code is Off
Trackbacks are Off
Pingbacks are Off
Refbacks are Off
Forum Jump


All times are GMT -7. The time now is 07:44 AM.


Powered by vBulletin® Version 3.7.3
Copyright ©2000 - 2009, Jelsoft Enterprises Ltd.
SEO by vBSEO 3.2.0 ©2008, Crawlability, Inc.
©2005 - 2009 Math Help Forum


Math Help Forum is a community of maths forums with an emphasis on maths help in all levels of mathematics.
Register to post your math questions or just hang out and try some of our math games or visit the arcade.