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Old December 2nd, 2008, 02:46 PM
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Default Help with rationalizing expressions

I need help with a couple of rationalization questions. I am totally confused.

square root 5x minus 6 / squareroot 5x plus 3


(squareroot 2+y plus squareroot 2-y)/y
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  #2  
Old December 2nd, 2008, 03:23 PM
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I need help with a couple of rationalization questions. I am totally confused.

square root 5x minus 6 / squareroot 5x plus 3


(squareroot 2+y plus squareroot 2-y)/y
Is it

(1) \frac{\sqrt{5x-6}}{\sqrt{5x+3}} ?

or

(2) \frac{\sqrt{5x}-6}{\sqrt{5x}+3}

Also group what's under the radical in your second problem as well.
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Old December 2nd, 2008, 03:52 PM
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for the second questions it's 2+y under squareroot symbol minus 2-y under squareroot symbol all over y

how do you enter info in the format you're using? It'd be much easier to post if I knew how to do that.
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Old December 3rd, 2008, 01:16 AM
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for the second questions it's 2+y under squareroot symbol minus 2-y under squareroot symbol all over y

how do you enter info in the format you're using? It'd be much easier to post if I knew how to do that.

Have a look here: http://www.mathhelpforum.com/math-he...-tutorial.html
Use a factor such that you get a sum of squares in the denominator:

\dfrac{\sqrt{5x} - 6}{\sqrt{5x} + 3}=\dfrac{\sqrt{5x} - 6}{\sqrt{5x} + 3} \cdot \dfrac{\sqrt{5x} - 3}{\sqrt{5x} - 3}= \dfrac{5x-9\sqrt{5x} +18}{5x-9}
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Old December 3rd, 2008, 12:21 PM
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Thanks Earboth.

Hopefully this works right. The other question I need help with is:

\frac{\sqrt{2+y} + \sqrt{2-y}}{y}

Last edited by shiel8; December 3rd, 2008 at 12:36 PM. Reason: fixing latex
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