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January 1st, 2009, 09:45 AM
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| | quadratics help needed I need to solve for x in these two question; x: -3x2 + 4x = 4 x: x2 + 3x + 4 = 0 I'm quite sure there will be two awnsers for each question I tried plugging in the numbers into this formula -b+/- sqrt> b^2 -4(a)(c)/2a i need somebodies help because my arithmatic is bad, and i cant seem to get a whole number as my awnser so im stuck | 
January 1st, 2009, 10:27 AM
|  | Bar0n | | Join Date: Apr 2007 Location: South Africa
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Originally Posted by 14041471 I need to solve for x in these two question; x: -3x2 + 4x = 4 x: x2 + 3x + 4 = 0 I'm quite sure there will be two awnsers for each question I tried plugging in the numbers into this formula -b+/- sqrt> b^2 -4(a)(c)/2a i need somebodies help because my arithmatic is bad, and i cant seem to get a whole number as my awnser so im stuck | Correct, they are not whole numbers, and the roots are complex.
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January 1st, 2009, 11:31 AM
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| | reply i no you've helped me out alot already, but i really cant awnser this question. could you solve it for me and then mabe i could see how it is like that.. | 
January 1st, 2009, 01:05 PM
|  | Bar0n | | Join Date: Apr 2007 Location: South Africa
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Originally Posted by 14041471 i no you've helped me out alot already, but i really cant awnser this question. could you solve it for me and then mabe i could see how it is like that.. | You said you plugged it into the quadratic formula. That is all you need to do.
I will do the second one for you. The first one you must attempt on your own. 
OR
Thus: 
OR
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Last edited by janvdl; January 1st, 2009 at 01:06 PM.
Reason: Forgot complex stuff
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January 1st, 2009, 01:45 PM
|  | Flow Master | | Join Date: Dec 2007 Location: Zeitgeist
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Originally Posted by 14041471 i no you've helped me out alot already, but i really cant awnser this question. could you solve it for me and then mabe i could see how it is like that.. | It would be easier to help you and point out your mistakes if you showed the work you've done.
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