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Old January 11th, 2009, 06:15 PM
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Default synthetic division

I was given the problem to divide

[x^5 - (1/3)x^4 +2x - 3] by (2x-3)

using synthetic division.

im stuck because (2x-3) needs to be in the form of (x-c)

any help is greatly appreciated
thanks, Jeremiah
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Old January 11th, 2009, 06:21 PM
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2x -3 = 2(x-\frac{3}{2})
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Old January 11th, 2009, 06:46 PM
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what would happen to the 2 out in front?
when i do the synthetic division i come up with

x^4 - (11/6)x^3 + (11/4)x^2 - (33/8)x +(131/16) remainder (-489/32)

could this be a valid answer? or am i doing something wrong?
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Old January 11th, 2009, 07:12 PM
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\frac{95}{32} + \frac{21x}{16} + \frac{7x^2}{8} + \frac{7x^3}{12} + \frac{x^4}{2}
Remainder \frac{189}{32}
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