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Old November 1st, 2009, 11:47 AM
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Default find all z values

find all values for z for the following equation:

z^2 + 2iRe(z) = |z|

I tried
|z|^2 \cdot (cos 2\phi + i \cdot sin 2\phi) + 2i \cdot a = |z|

|z| \cdot (cos 2\phi + i \cdot sin 2\phi) + \frac{2i \cdot a}{|z|} = 1

what do i do now? can someone show me how to continue (or solve it if possible)?
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Old November 1st, 2009, 08:33 PM
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Originally Posted by metlx View Post
find all values for z for the following equation:

z^2 + 2iRe(z) = |z|

I tried
|z|^2 \cdot (cos 2\phi + i \cdot sin 2\phi) + 2i \cdot a = |z|

|z| \cdot (cos 2\phi + i \cdot sin 2\phi) + \frac{2i \cdot a}{|z|} = 1

what do i do now? can someone show me how to continue (or solve it if possible)?

Put z = x + yi, so your equation is:

x^2-y^2+2x(y+1)i =\sqrt{x^2+y^2}, and compare real and imaginary parts:

==\,\,x^2-y^2=\sqrt{x^2+y^2}
==\,\,2x(y+1)=0\Longrightarrow x=0\,\,or\,\,y=-1 and etc.

Tonio
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