| 
November 1st, 2009, 12:07 PM
| | Junior Member | | Join Date: Sep 2009
Posts: 54
Country: Thanks: 33
Thanked 0 Times in 0 Posts
| | Please Help Solve this equation e^(5x-3) = 10
I am not sure how to solve this because of the e.
Any help is appreciated. | 
November 1st, 2009, 12:21 PM
|  | MHF Contributor | | Join Date: Jun 2008 Location: North Texas
Posts: 6,269
Country: Thanks: 52
Thanked 2,690 Times in 2,539 Posts
| | Quote:
Originally Posted by tsmith e^(5x-3) = 10
I am not sure how to solve this because of the e.
Any help is appreciated. | take the natural log of both sides ...
solve for  as usual | | The following users thank skeeter for this useful post: | |  | 
November 1st, 2009, 12:29 PM
| | Junior Member | | Join Date: Sep 2009
Posts: 54
Country: Thanks: 33
Thanked 0 Times in 0 Posts
| | so x would = 1.0606? | 
November 1st, 2009, 12:31 PM
|  | MHF Contributor | | Join Date: Jun 2008 Location: North Texas
Posts: 6,269
Country: Thanks: 52
Thanked 2,690 Times in 2,539 Posts
| | Quote:
Originally Posted by tsmith so x would = 1.0606? | are you able to check your solution in the original equation? | 
November 1st, 2009, 12:36 PM
| | Junior Member | | Join Date: Sep 2009
Posts: 54
Country: Thanks: 33
Thanked 0 Times in 0 Posts
| | yes | | Thread Tools | | | | Display Modes | Linear Mode |
Posting Rules
| You may not post new threads You may not post replies You may not post attachments You may not edit your posts HTML code is Off | | | All times are GMT -7. The time now is 06:51 AM. | | |
 | |  |