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Old November 3rd, 2009, 12:51 AM
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Default convergence

a is the real number ,Studen the convergence of the sequence :
U_{n}=\frac{a^{n}}{n^{n}}
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Old November 3rd, 2009, 04:36 AM
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U_n = \left( \frac{a}{n} \right)^n

You said sequence, not series, so this question is about the behavior of U_n as n approaches infinity. I would start with assuming \lim_{n \rightarrow \infty} U_n = L and play around with that, most likely using logarithms.
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