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Old November 11th, 2009, 06:46 PM
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Given a circle with center O, PQ AND PR are two tangents from point P outside the circle. Prove that angle POQ = angle POR.
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Old November 11th, 2009, 10:12 PM
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Originally Posted by shane99 View Post
Given a circle with center O, PQ AND PR are two tangents from point P outside the circle. Prove that angle POQ = angle POR.
So the triangles share a common hypotenuse PO. We know the two radii are congruent: OQ\cong OR. Since \angle PQO=90^o=\angle PRO (tangent lines to a circle form right angles with the radius), the two triangles are congruent by HL, and the two desired angles are congruent by CPCTC.
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