Solving for x

Neconine · #1 $Old$ November 16th, 2009, 10:26 AM

I'm not sure how to solve this question:

2^2x - 3(2^x) +2 = 0

Appreciate any help

Thanks

ukorov · #2 $Old$ November 16th, 2009, 10:36 AM

Quote:

Originally Posted by Neconine $View Post$

I'm not sure how to solve this question:

2^2x - 3(2^x) +2 = 0

Appreciate any help

Thanks

Let y = 2^x
So we have y^2 - 3y + 2 = 0
(y - 2)(y - 1) = 0
y = 2 or y = 1
Therefore 2^x = 2, x = 1
or 2^x = 1, x = 0

Neconine · #3 $Old$ November 16th, 2009, 10:43 AM

Quote:

Originally Posted by ukorov $View Post$

Let y = 2^x
So we have y^2 - 3y + 2 = 0
(y - 2)(y - 1) = 0
y = 2 or y = 1
Therefore 2^x = 2, x = 1
or 2^x = 1, x = 0

Thanks a lot!