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Old November 17th, 2009, 03:58 PM
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I have 3 vectors a = 2i - j + k, b = i -j +k, c= -i - 2j + 2k

I have to find:

1) the value of w when a + wb is orthogonal to c

2) The value(s) of w that make c at 45 degrees to -i + wk

The answers are:

1) 4/3

2) 1,7

I have tried this and no matter what I do I cannot get these answers. Please help. Though to be honest I'm not sure where to start other than:

x1x2 + y1y2 + z1z2 = 0

Can anyone help?
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Old November 22nd, 2009, 02:47 PM
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Quote:
Originally Posted by JQ2009 View Post
I have 3 vectors a = 2i - j + k, b = i -j +k, c= -i - 2j + 2k

I have to find:

1) the value of w when a + wb is orthogonal to c

2) The value(s) of w that make c at 45 degrees to -i + wk

The answers are:

1) 4/3

2) 1,7

I have tried this and no matter what I do I cannot get these answers. Please help. Though to be honest I'm not sure where to start other than:

x1x2 + y1y2 + z1z2 = 0

Can anyone help?
Both of these tasks use the definition of the dot product:
cos(a,b) = (a*b) / (|a||b|) where |a| and |b| are the lengths of the vectors and a*b is the dot product of a and b. Cos(a,b) means the angle between vectors a and b.

2) We have vectors c= -i - 2j + 2k and u = -i + wk . The angle wanted here is 45°, and cos (45°) = 1/sqrt(2).
Also,
c*u = (-1)(-1) + -2*0 + 2*w = 1 + 2w
|c| = sqrt(1 +4 +4) = sqrt(9) = 3
|u] = sqrt(1² + w²)

Then we use the definition of the dot product cos(a,b) = (a*b) / (|a||b|)
to get an equation where we can solve w:

1/sqrt(2) = (1+2w) / 3*sqrt(1+w²)

And we'll get w = 1 or w = 7.

I can't seem to get 4/3 ( I get -2/3, I might have calculated something wrong) in 1) , but the idea is similar: vectors u and v can only be orthogonal to each other (= the angle between them is 90°) when the dot product u*v = cos(90°) = 0
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