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#1

$Old$ June 25th, 2007, 01:22 PM

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i need to find the focus of the parabola in this equation:

(x-1)^2 + 32 = 8y

plz help

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$Old$ June 25th, 2007, 01:33 PM

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Hello, angeldri!

I must assume you know the standard forms for a parabola.

Quote:

Find the focus of the parabola: . $(x-1)^2 + 32 \;= \;8y$

We have: . $(x-1)^2 \;=\;8y - 32\quad\Rightarrow\quad(x-1)^2 \;=\;8(y-4)$

This is an up-opening parabola with vertex at $(1,4)$ and $p = 2.$

The focus is 2 units above the vertex: . $F(1,6)$

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