Find The Y Intercept - Urgent

mibamars · #1 $Old$ June 25th, 2007, 10:13 PM

I need serious help.

I need to find the Y intercept of the graph

$y= -0.02(x^3 - 38x^2 + 441x - 1620)$

I also need to X when y=3

I also need to find the equation of the inclined path if it hasa gradient of 4/5

Please help

Jhevon · #2 $Old$ June 25th, 2007, 10:15 PM

for the y-intercept, just plug in x = 0

mibamars · #3 $Old$ June 25th, 2007, 10:17 PM

Awesome. Any help with the others?

Jhevon · #4 $Old$ June 25th, 2007, 10:29 PM

Quote:

Originally Posted by mibamars $View Post$

$y= -0.02(x^3 - 38x^2 + 441x - 1620)$

I also need to X when y=3

$y= -0.02(x^3 - 38x^2 + 441x - 1620)$

when $y = 3$ we have

$3= -0.02(x^3 - 38x^2 + 441x - 1620)$

$\Rightarrow x^3 - 38x^2 + 441x - 1470 = 0$

Trying the factors of 1470, we realize that x = 14 is a root, so (x - 14) is a factor. Dividing the cubic by (x - 14) using long division, we obtain:

$x^3 - 38x^2 + 441x - 1470 = (x - 14) \left( x^2 - 24 x + 105 \right) = 0$

$\Rightarrow x - 14 = 0 \mbox { or } x^2 - 24x + 105 = 0$

$\Rightarrow x = 14 \mbox { or } x = \frac {24 \pm \sqrt {156}}{2}$

Quote:

Originally Posted by mibamars $View Post$

I also need to find the equation of the inclined path if it hasa gradient of 4/5

when you say inclined path you mean tangent line right?