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#1

$Old$ 11-19-2008, 05:07 PM

live_laugh_luv27 $live_laugh_luv27 is offline$

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$Question$ Imaginary Numbers

Suppose that x and y are real numbers such that (2+3x)-(5-3y)i = 11+7i.
Find the values of x and y.

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#2

$Old$ 11-19-2008, 06:09 PM

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How about equating the REAL part of the left side of equation to the REAL part of the right side of equation?Then equate the IMAGINARY parts of the two sides in the same sense!

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$Old$ 11-19-2008, 06:12 PM

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(2+3x)-(5-3y)i = 11+7i.

So...
2+3x = 11 and (5-3y)i = 7i ???

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$Old$ 11-19-2008, 06:15 PM

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Quote:

Originally Posted by live_laugh_luv27 $View Post$

(2+3x)-(5-3y)i = 11+7i.

So...
2+3x = 11 and - (5-3y)i = 7i ???

yes. but you could have left off the i's. doesn't really matter in the end, but it looks awkward. and you have to carry the minus sign! i put it in in red

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