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Old 11-19-2008, 06:04 PM
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Post Quadratic equation

A quadratic equation x^2 + bx + c = 0 has complex roots 3+6i and 3-6i. Find the values of b and c.

Thank you for any help!
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Old 11-19-2008, 06:09 PM
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A quadratic equation x^2 + bx + c = 0 has complex roots 3+6i and 3-6i. Find the values of b and c.

Thank you for any help!
hint: the coefficients of the x-squared term in the quadratic is 1, thus the quadratic is given by (x - r_1)(x - r_2), where r_1 and r_2 are the two roots of the equation
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Old 11-19-2008, 06:19 PM
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Originally Posted by Jhevon View Post
hint: the coefficients of the x-squared term in the quadratic is 1, thus the quadratic is given by (x - r_1)(x - r_2), where r_1 and r_2 are the two roots of the equation

So, would you do (1-(3+6i )) and (1-(3-6i))??
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Old 11-19-2008, 06:21 PM
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So, would you do (1-(3+6i )) and (1-(3-6i))??
i have no idea how you got that

to follow up on what i said, start with (x - 3 - 6i)(x - 3 + 6i)

now multiply out and you can find b and c
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Old 11-19-2008, 06:25 PM
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Originally Posted by Jhevon View Post
i have no idea how you got that

to follow up on what i said, start with (x - 3 - 6i)(x - 3 + 6i)

now multiply out and you can find b and c

Thank you so much for your help!!
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Old 11-19-2008, 06:28 PM
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Thank you so much for your help!!
you're welcome

state your answer when done
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Old 11-19-2008, 06:29 PM
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you're welcome

state your answer when done
b = -9, c=45
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Old 11-19-2008, 06:33 PM
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b = -9, c=45
b is incorrect
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Old 11-19-2008, 06:36 PM
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-6 !!!!!!!!!!!
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Old 11-19-2008, 06:37 PM
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-6 !!!!!!!!!!!
um, yes...!!!!!!!!!!!!
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