expanding expression using properties of logarithms - Math Help Forum

$Math Help Forum$

$Go Back$		Math Help Forum > High School Math Help > Pre-Calculus
$Reload this Page$ expanding expression using properties of logarithms

Mark Forums Read

$Reply$

#1

$Old$ 11-21-2008, 01:10 AM

Kitty216 $Kitty216 is offline$

Member

Join Date: Aug 2008

Posts: 40

Country:

United States

Thanks: 19

Thanked 0 Times in 0 Posts

$Kitty216 is on a distinguished road$

$Default$ expanding expression using properties of logarithms

Use the properties of logarithms to expand the expression.

Can anyone help me with this one?

$Reply With Quote$

Advertisement

#2

$Old$ 11-21-2008, 11:30 AM

$Moo's Avatar$

$Moo is offline$

A Cute Angle

Join Date: Mar 2008

Location: Green and fresh grass

Posts: 4,083

Thanks: 361

Thanked 2,090 Times in 1,741 Posts

$Moo has a reputation beyond repute$ $Moo has a reputation beyond repute$ $Moo has a reputation beyond repute$ $Moo has a reputation beyond repute$ $Moo has a reputation beyond repute$ $Moo has a reputation beyond repute$ $Moo has a reputation beyond repute$ $Moo has a reputation beyond repute$ $Moo has a reputation beyond repute$ $Moo has a reputation beyond repute$ $Moo has a reputation beyond repute$

$Default$

Hello,

Ummm well, the only log properties you can use are :
$\ln(ab)=\ln(a)+\ln(b)$
$\ln \left(\frac ab \right)=\ln(a)-\ln(b)$
$\ln \left(a^b\right)=b \ln(a)$

So here we have :
$\ln \left[\frac{(3x^6+2) \sqrt{x+8}}{(x-1)^4}\right]=\ln [3x^6+2]+\ln \left[\sqrt{x+8}\right]-\ln \left[(x-1)^4\right]$
that was using the first 2 properties.

now use the last one :
$=\ln [3x^6+2]+\frac 12 \cdot \ln [x+8]-4 \ln [x-1]$

but it doesn't look more beautiful

__________________
Arbeit bringt Brot, Faulenzen Hungersnot.
Everything is possible. The impossible just takes longer.

shinhidora production

$Reply With Quote$

The following users thank Moo for this useful post:
Kitty216
$Donate to MHF$

#3

$Old$ 11-21-2008, 04:17 PM

Kitty216 $Kitty216 is offline$

Member

Join Date: Aug 2008

Posts: 40

Country:

United States

Thanks: 19

Thanked 0 Times in 0 Posts

$Kitty216 is on a distinguished road$

$Default$

oh

Skype Speechless

I thought there was much more to it haha.. wow it looked more beautiful just the way it was in the beginning XD.

Thanks for the help!

$Reply With Quote$

$Reply$

« Matrix Determinant / Complex numbers. | Dual Problem & Simplex Tableau - Part 2 »

Thread Tools
$Show Printable Version$ Show Printable Version $Email this Page$ Email this Page
Display Modes
$Linear Mode$ Linear Mode $Hybrid Mode$ Switch to Hybrid Mode $Threaded Mode$ Switch to Threaded Mode

Posting Rules
You may not post new threads You may not post replies You may not post attachments You may not edit your posts BB code is On Smilies are On [IMG] code is On HTML code is Off Trackbacks are Off Pingbacks are Off Refbacks are Off

Forum Jump

All times are GMT -7. The time now is 05:41 PM.

your link here Sponsors

rv solar, e-learning, Hypnosis | Buy Anything On eBay | Credit Counseling | Bad Credit Mortgages | Myspace Proxy

Math Help Forum is a community of maths forums with an emphasis on maths help in all levels of mathematics.
Register to post your math questions or just hang out and try some of our math games or visit the arcade.