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November 21st, 2008, 01:23 PM
| | Newbie | | Join Date: Sep 2008
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| | Is this question flawed? I am given the equation of a curve: y=x^3 - 5x - (2/x) where x is not equal to 0.
I am told that the points A and B which are (1,-2) and (-1,2) lie on it.
However, when one substitutes 1 and -1 into the equation one gets: -6 and 6 respectively.
I am pretty sure i am not going mad and this is a misprint (it is supposed to be a past exam question from what i gather.)
Am i right?
Thanks | 
November 21st, 2008, 01:47 PM
|  | Eater of Worlds | | Join Date: Jul 2006 Location: Chaneysville, PA
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| | There is a typo in the equation.
If it were  , then it'll work OK. | 
November 21st, 2008, 01:48 PM
|  | Grand Panjandrum | | Join Date: Nov 2005 Location: South of England
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| | Quote:
Originally Posted by StaryNight I am given the equation of a curve: y=x^3 - 5x - (2/x) where x is not equal to 0.
I am told that the points A and B which are (1,-2) and (-1,2) lie on it.
However, when one substitutes 1 and -1 into the equation one gets: -6 and 6 respectively.
I am pretty sure i am not going mad and this is a misprint (it is supposed to be a past exam question from what i gather.)
Am i right?
Thanks | Prabably y=x^3 - 5x + (2/x) was intended.
CB
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