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Old November 25th, 2008, 02:10 AM
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Default Bearing word problems help

They are driving me crazy. Please help..

1.) A plane took off on a runway having a bearing of 75 degrees. After flying for 1.5 miles, the pilot turned 90degrees and headed toward northwest. After the plane goes 3 miles in this direction, what bearing should the control tower use to locate the aircraft?


2.) Two ships leave a pier at the same time. Ship A sails in the direction of 55degrees at 20 knots while ship b sails in the direction of 145 at 25 knots. Determine after traveling 3 hrs the distance between the ships. What is the bearing of ship A from ship B?

3.) A ship leaves a port and sails for 3 hrs on a course N78degrees E at 12 knots. Then the ship changes its course to 168degrees and sails for 5 hours at 10 knots. After 8 hours, how far is the ship from the port? Determine the bearing of the ship from the port.


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Please help.. Thank you very much!
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Old November 25th, 2008, 03:05 AM
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The first step is to draw a diagram (assuming you aren't using vectors yet). I have drawn it for the first one.
bearing-word-problems-help-dtfd.jpg

Then just start filling in the things you can deduce from the picture.
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Old November 25th, 2008, 06:41 AM
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Hello, fayeorwhatsoever!

Quote:
3) A ship leaves a port and sails for 3 hrs on a course N78°E at 12 knots.
Then the ship changes its course to 168° and sails for 5 hours at 10 knots.
After 8 hours, how far is the ship from the port?
Determine the bearing of the ship from the port.
Code:
      N       M
      :       :
      :       :
      :     A o 168°
      :      *  * 
      :     * 90° *
      :    *        *
      :78°* 36        *  50
      :  *              *
      : *                 *
      :*                    *
    P o                       *
            *                   *
                  *               * 
                        *           * 
                              *       * 
                                    *   *
                                          o B

The ship starts at port P. .\angle NPA = 78^o
It sails 36 nautical miles to A.

It changes course to \angle MAB = 168^o
. . and sails 50 nautical miles to B.
Note that \angle PAB = 90^o.

Pythagorus: .PB^2 \:=\:36^2 + 50^2 \:=\:3796 \quad\Rightarrow\quad PB \:=\:\sqrt{3796} \:\approx\:61.6

The ship is about 61.6 nautical miles from the port.



In right triangle PAB\!:\;\;\tan(P) \:=\:\tfrac{50}{36} \quad\Rightarrow\quad P \:=\:\tan^{-1}\left(\tfrac{50}{36}\right) \:\approx\:54.2^o

The bearing is: .\angle NPB \;=\;78^o + 54.2^o \;=\;132.2^o

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