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#1

$Old$ November 25th, 2008, 02:27 AM

Faz $Faz is offline$

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(x-2)^2 + (y-2)^2 =2
what does the graph look like is it like a circle on the 2nd quadrant

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#2

$Old$ November 25th, 2008, 02:51 AM

badgerigar $badgerigar is offline$

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The graph is indeed a circle, but it is in the first quadrant. To find the radius and centre, put the equation into the form $(x-h)^2+(y-k)^2 = r^2$ . Then (h,k) is the centre and r is the radius.

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