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#1

$Old$ November 25th, 2008, 02:30 PM

adeshSB $adeshSB is offline$

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$Default$ co ordinate geometry

can anyone help??
got this question,,
The points ABC have co ordinates (2, 1) (b,3) and (5,5) where b>3
and angle ABC=90degrees ??
I know the answer just have no idea how to work it out.

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#2

$Old$ November 25th, 2008, 02:39 PM

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(slope of AB)(slope of BC) = -1

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$Old$ November 25th, 2008, 02:43 PM

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In a right triangle $a^2 + b^2 = c^2$ .
So $(b-2)^2 +(3-1)^2 + (b-5)^2 + (3-5)^2 = (5-2)^2 + (5-1)^2$

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$Old$ November 25th, 2008, 03:02 PM

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does that make b= 6
cause i justtried and got some strange answer sorry i'm a bit rubbish at this

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Originally Posted by Plato $View Post$

In a right triangle $a^2 + b^2 = c^2$ .
So $(b-2)^2 +(3-1)^2 + (b-5)^2 + (3-5)^2 = (5-2)^2 + (5-1)^2$

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angle, co-ordinate, finding, geometry

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