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#1

$Old$ December 2nd, 2008, 09:55 PM

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$Default$ polar coordinates

transform the given polar equation to rectangular coordinates

a) r = 5sec(theta)

b) r = sec(theta)tan(theta)

c) r = 4cos(theta) + 4sin(theta)

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#2

$Old$ December 2nd, 2008, 10:05 PM

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Originally Posted by noles2188 $View Post$

transform the given polar equation to rectangular coordinates

a) r = 5sec(theta) Mr F says: ${\color{red}\Rightarrow r cos \theta = 5}$ ....

b) r = sec(theta)tan(theta) Mr F says: ${\color{red}\Rightarrow r \cos \theta = \frac{\sin \theta}{\cos \theta} = \frac{y/r}{x/r} = \frac{y}{x}}$ ....

c) r = 4cos(theta) + 4sin(theta) Mr F says: ${\color{red}\Rightarrow r = 4 \frac{x}{r} + 4 \frac{y}{r} \Rightarrow r^2 = 4x + 4y}$ ....

.... means the rest is left for you to finish off.

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