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Old December 16th, 2008, 09:28 AM
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Exclamation Parallel/Perpendicular Lines

So here's the problem: passes through (-2,2), parallel to graph of -2x + y = 4. Then I graph the line that satisfies the condition, but what I really need to know is just how to figure out the slope.
Exams tomorrow... please help me!
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Old December 16th, 2008, 09:41 AM
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So here's the problem: passes through (-2,2), parallel to graph of -2x + y = 4. Then I graph the line that satisfies the condition, but what I really need to know is just how to figure out the slope.
Parallel have the same slope.
So any line parallel to -2x + y = 4 looks like -2x + y = K.
Just substitute the values for x & y to find K.
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Old December 16th, 2008, 09:45 AM
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So here's the problem: passes through (-2,2), parallel to graph of -2x + y = 4. Then I graph the line that satisfies the condition, but what I really need to know is just how to figure out the slope.
Exams tomorrow... please help me!
When lines are parallel, they have the same slope. [i.e. if the slope of one line is m=a then line two has a slope of m_{\parallel}=a

When lines are perpendicular, its a little different. If line one has a slope of m=a, then line two has a slope of m_{\bot}=-\frac{1}{a}
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