X and Y intercepts--multiple choice

janedoe · #1 $Old$ January 7th, 2009, 12:23 PM

http://i40.tinypic.com/34647dd.jpg
I explained more here^^, where I included the problem.

Thanks for any input!

earboth · #2 $Old$ January 7th, 2009, 12:31 PM

Quote:

Originally Posted by janedoe $View Post$

http://i40.tinypic.com/34647dd.jpg
I explained more here^^, where I included the problem.

Thanks for any input!

The domain of your function is $d = \mathbb{R}_0^+$ .

Therefore x and y-intercepts are at x = 0 and y = 0.

janedoe · #3 $Old$ January 7th, 2009, 12:39 PM

That's what I thought, but it's not an answer =[ it's possible it could be an error...or is it one of those choices?

earboth · #4 $Old$ January 7th, 2009, 12:52 PM

Quote:

Originally Posted by janedoe $View Post$

That's what I thought, but it's not an answer =[ it's possible it could be an error...or is it one of those choices?

From all possible choices I would have taken:

x-intercepts: (0,0) , (-2); y-intercepts: (0,0)

But I'm confused about the single (-2) and I've no idea what is meant by that.