Converting Polar equations into rectangular equations:

Neversh · #1 $Old$ June 8th, 2009, 06:34 PM

How do I convert r = 5sin(x) into an equivalent rectangular equation?

Amer · #2 $Old$ June 8th, 2009, 08:09 PM

Quote:

Originally Posted by Neversh $View Post$

How do I convert r = 5sin(x) into an equivalent rectangular equation?

you mean

$r=5sin(\theta)$ to rectangular

you should know that

$x=r cos(\theta)$

$y=r sin(\theta)$

$\sqrt{x^2+ y^2 } = r.....x^2+y^2=r^2$

use them to find the equation try

Soroban · #3 $Old$ June 8th, 2009, 08:10 PM

Hello, Neversh!

You know the conversion, right?

. . $\begin{array}{c}r\cos\theta \:=\:x \\ r\sin\theta \:=\:y \\ r^2 \:=\:x^2+y^2 \end{array}$

Quote:

How do I convert $r = 5\sin\theta$ into an equivalent rectangular equation?

We have: . $r \:=\:5\sin\theta$

$\text{Multiply by }r\!:\;\;\underbrace{r^2} \:=\:5\underbrace{r\sin\theta}$
. - . - . . . . . . . $\uparrow\qquad\qquad\: \uparrow$
. . . . . . . . . . $^{x^2+y^2}\qquad\quad\;\; ^y$

And we have: . $x^2+y^2 \:=\:5y$

TheEmptySet · #4 $Old$ June 8th, 2009, 08:13 PM

Quote:

Originally Posted by Neversh $View Post$

How do I convert r = 5sin(x) into an equivalent rectangular equation?

First multiply both sides by r to get

$r^2=5r\sin(x)$

Now we know that $r^2=x^2+y^2$ and

$r\sin(x)=y$

Now we get

$x^2+y^2=5y \iff x^2+y^2-5y=0 \iff x^2+y^2-5y+\frac{25}{4}=\frac{25}{4}$

So finally we get

$x^2+\left(y-\frac{5}{2} \right)^2=\left( \frac{5}{2}\right)^2$

Edit too slow haha