Hello all,

I've been out of high school for many years and just started Trigonomtry and cannot fiqure out this problem to save my life. I would appreciate any help. Thank you in advance

In isosceles (picture a triangle)ABC, AB +AC, (picture a angle)C = 70 degrees, and BC = 4.0 cm.
calculate the height of the triangle to the nearest millimetre

Does anyone have any ideas?

I fiqured out the problem: 70 TAN = 2.7474 X 2 = 5.5 to the nearest millimetre. Apparently there's two right angles in an isosceles. Thanks anyways

Hi Amry,

You may have figured out the answer, but your last statement is worded incorrectly. I think you meant to say that the altitude drawn from the vertex angle is perpendicular to the base, thus forming 2 right angles. But they're not in the same triangle. You split the isosceles triangle into 2 congruent right triangles.

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