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#1

$Old$ March 26th, 2006, 03:34 PM

c_323_h $c_323_h is offline$

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solve the trig equation sec(x)-2=0 for exact solutions in the interval
0<= x <= 2pi

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#2

$Old$ March 26th, 2006, 04:39 PM

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Originally Posted by c_323_h

solve the trig equation sec(x)-2=0 for exact solutions in the interval
0<= x <= 2pi

sec(x)=2

Now, sec=1/cos

Thus cos(x)=1/2.

So for what values of x is cos(x)=1/2?

-Dan

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$Old$ March 26th, 2006, 04:39 PM

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Originally Posted by c_323_h

solve the trig equation sec(x)-2=0 for exact solutions in the interval
0<= x <= 2pi

That means,
$\sec x=2$
because secant is reciprocal function of cosine we have,
$\cos x=\frac{1}{2}$ for $0<x<2\pi$
Thus,
$x=\frac{\pi}{6},\frac{11\pi}{6}$

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$Old$ March 26th, 2006, 04:45 PM

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i've got pi/3 and 5pi/3

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$Old$ March 26th, 2006, 05:17 PM

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i've got pi/3 and 5pi/3

Yup. ThePerfectHacker isn't having a good day with trig. I hope he's okay...

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#6

$Old$ March 26th, 2006, 05:22 PM

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Yup. ThePerfectHacker isn't having a good day with trig. I hope he's okay...

-Dan

No I am so tired now. Not really realizing what I am doing.
If I make another mistake I am leaving this site for today.

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$Old$ March 26th, 2006, 05:26 PM

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No I am so tired now. Not really realizing what I am doing.
If I make another mistake I am leaving this site for today.

It's okay. We still love you. Get some sleep for me!

-Dan

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