Math Help Forum

Math Help Forum Feed Site Feed

Go Back   Math Help Forum > Pre-University Math Help > Trigonometry
Reply
 
Thread Tools Display Modes
  #1  
Old July 4th, 2009, 12:11 AM
Junior Member
 
Join Date: Jul 2009
Posts: 31
Country:
Thanks: 15
Thanked 0 Times in 0 Posts
matsci0000 is on a distinguished road
Question Identities

If cosec A +secA=cosecB+secB , prove that tanA tanB=cot{(A+B)/2}


Reply With Quote
Advertisement
 
  #2  
Old July 4th, 2009, 12:32 AM
red_dog's Avatar
MHF Contributor
 
Join Date: Jun 2007
Location: Medgidia, Romania
Posts: 1,169
Country:
Thanks: 22
Thanked 621 Times in 562 Posts
red_dog is a splendid one to beholdred_dog is a splendid one to beholdred_dog is a splendid one to beholdred_dog is a splendid one to beholdred_dog is a splendid one to beholdred_dog is a splendid one to beholdred_dog is a splendid one to behold
Default

\frac{1}{\sin A}+\frac{1}{\cos A}=\frac{1}{\sin B}+\frac{1}{\cos B}\Rightarrow

\Rightarrow\frac{1}{\sin A}-\frac{1}{\sin B}=\frac{1}{\cos B}-\frac{1}{\cos A}\Rightarrow

\frac{\sin B-\sin A}{\sin A\sin B}=\frac{\cos A-\cos B}{\cos A\cos B}\Rightarrow\frac{\sin A\sin B}{\cos A\cos B}=\frac{\sin B-\sin A}{\cos A-\cos B}\Rightarrow

\tan A\tan B=\frac{2\sin\frac{B-A}{2}\cos\frac{A+B}{2}}{2\sin\frac{B-A}{2}\sin\frac{A+B}{2}}=\cot\frac{A+B}{2}
Reply With Quote
The following users thank red_dog for this useful post:
Donate to MHF
Reply

Thread Tools
Display Modes

Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

BB code is On
Smilies are On
[IMG] code is On
HTML code is Off
Trackbacks are Off
Pingbacks are Off
Refbacks are Off
Forum Jump


All times are GMT -7. The time now is 12:02 PM.


Powered by vBulletin® Version 3.7.3
Copyright ©2000 - 2009, Jelsoft Enterprises Ltd.
SEO by vBSEO 3.2.0 ©2008, Crawlability, Inc.
©2005 - 2009 Math Help Forum


Math Help Forum is a community of maths forums with an emphasis on maths help in all levels of mathematics.
Register to post your math questions or just hang out and try some of our math games or visit the arcade.